3-2.Motion in Plane
easy

As a part of a maintenance inspection the compressor of a jet engine is made to spin according to the graph as shown. The number of revolutions made by the compressor during the test is 

A

$9000$

B

$16570$

C

$12750$

D

$11250$

Solution

Number of revolution = Area between the graph and time axis = Area of trapezium

= $\frac{1}{2} \times (2.5 + 5) \times 3000$ = $11250$ revolution.

Standard 11
Physics

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